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x^2-21=465
We move all terms to the left:
x^2-21-(465)=0
We add all the numbers together, and all the variables
x^2-486=0
a = 1; b = 0; c = -486;
Δ = b2-4ac
Δ = 02-4·1·(-486)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*1}=\frac{0-18\sqrt{6}}{2} =-\frac{18\sqrt{6}}{2} =-9\sqrt{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*1}=\frac{0+18\sqrt{6}}{2} =\frac{18\sqrt{6}}{2} =9\sqrt{6} $
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